James Tanton asked on Twitter: As there are “more” triang nmbrs than sq nmbrs http://www.jamestanton.com/?p=1009 let f(N) = nmbr triangs >= N^2 but < (N+1)^2. Curious:What graph like? The th triangular number is about (more precisely, it’s .) So there are about triangular numbers less than . Therefore, “on average”, in each interval there are [...]